Base | Representation |
---|---|
bin | 10110100111100110… |
… | …00110101101100011 |
3 | 1011100021210202220212 |
4 | 23103303012231203 |
5 | 144332142332003 |
6 | 5324545324335 |
7 | 606631356656 |
oct | 132363065543 |
9 | 34307722825 |
10 | 12143324003 |
11 | 5171654068 |
12 | 242a9366ab |
13 | 11b6a66b25 |
14 | 832a8989d |
15 | 4b1131dd8 |
hex | 2d3cc6b63 |
12143324003 has 2 divisors, whose sum is σ = 12143324004. Its totient is φ = 12143324002.
The previous prime is 12143323949. The next prime is 12143324029. The reversal of 12143324003 is 30042334121.
It is a strong prime.
It is an emirp because it is prime and its reverse (30042334121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12143324003 - 214 = 12143307619 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12143324003.
It is not a weakly prime, because it can be changed into another prime (12143324033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071662001 + 6071662002.
It is an arithmetic number, because the mean of its divisors is an integer number (6071662002).
Almost surely, 212143324003 is an apocalyptic number.
12143324003 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143324003 is an equidigital number, since it uses as much as digits as its factorization.
12143324003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 12143324003 its reverse (30042334121), we get a palindrome (42185658124).
The spelling of 12143324003 in words is "twelve billion, one hundred forty-three million, three hundred twenty-four thousand, three".
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