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12143354325 = 352161911391
BaseRepresentation
bin10110100111100110…
…01110000111010101
31011100021212022111220
423103303032013111
5144332144314300
65324550120553
7606631544244
oct132363160725
934307768456
1012143354325
115171674923
12242a950159
1311b6a7787b
14832a9695b
154b113ada0
hex2d3cce1d5

12143354325 has 12 divisors (see below), whose sum is σ = 20077012608. Its totient is φ = 6476455600.

The previous prime is 12143354299. The next prime is 12143354339. The reversal of 12143354325 is 52345334121.

It is not a de Polignac number, because 12143354325 - 29 = 12143353813 is a prime.

It is a super-2 number, since 2×121433543252 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 80955621 + ... + 80955770.

It is an arithmetic number, because the mean of its divisors is an integer number (1673084384).

Almost surely, 212143354325 is an apocalyptic number.

12143354325 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

12143354325 is a deficient number, since it is larger than the sum of its proper divisors (7933658283).

12143354325 is a wasteful number, since it uses less digits than its factorization.

12143354325 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161911404 (or 161911399 counting only the distinct ones).

The product of its digits is 43200, while the sum is 33.

Adding to 12143354325 its reverse (52345334121), we get a palindrome (64488688446).

The spelling of 12143354325 in words is "twelve billion, one hundred forty-three million, three hundred fifty-four thousand, three hundred twenty-five".

Divisors: 1 3 5 15 25 75 161911391 485734173 809556955 2428670865 4047784775 12143354325