Base | Representation |
---|---|
bin | 10110100111100110… |
… | …11100101101001001 |
3 | 1011100021222100111101 |
4 | 23103303130231021 |
5 | 144332203222324 |
6 | 5324551301401 |
7 | 606632213422 |
oct | 132363345511 |
9 | 34307870441 |
10 | 12143414089 |
11 | 5171705814 |
12 | 242a97a861 |
13 | 11b6a98b31 |
14 | 832ab0649 |
15 | 4b114d944 |
hex | 2d3cdcb49 |
12143414089 has 2 divisors, whose sum is σ = 12143414090. Its totient is φ = 12143414088.
The previous prime is 12143414053. The next prime is 12143414117. The reversal of 12143414089 is 98041434121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11313513225 + 829900864 = 106365^2 + 28808^2 .
It is an emirp because it is prime and its reverse (98041434121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12143414089 - 29 = 12143413577 is a prime.
It is not a weakly prime, because it can be changed into another prime (12143414009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071707044 + 6071707045.
It is an arithmetic number, because the mean of its divisors is an integer number (6071707045).
Almost surely, 212143414089 is an apocalyptic number.
It is an amenable number.
12143414089 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143414089 is an equidigital number, since it uses as much as digits as its factorization.
12143414089 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 37.
The spelling of 12143414089 in words is "twelve billion, one hundred forty-three million, four hundred fourteen thousand, eighty-nine".
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