Base | Representation |
---|---|
bin | 10001101010111100111… |
… | …111010110001101011111 |
3 | 11022002110020120212002012 |
4 | 101222330333112031133 |
5 | 124343442441001002 |
6 | 2325510531021435 |
7 | 153506522304203 |
oct | 21527477261537 |
9 | 4262406525065 |
10 | 1214351500127 |
11 | 4290048445a7 |
12 | 177423a3a87b |
13 | 8a68898680c |
14 | 42abc57cb03 |
15 | 218c4b01d52 |
hex | 11abcfd635f |
1214351500127 has 4 divisors (see below), whose sum is σ = 1215155175696. Its totient is φ = 1213547824560.
The previous prime is 1214351500097. The next prime is 1214351500129. The reversal of 1214351500127 is 7210051534121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1214351500127 - 234 = 1197171630943 is a prime.
It is a super-2 number, since 2×12143515001272 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1214351500093 and 1214351500102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1214351500129) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401835518 + ... + 401838539.
It is an arithmetic number, because the mean of its divisors is an integer number (303788793924).
Almost surely, 21214351500127 is an apocalyptic number.
1214351500127 is a deficient number, since it is larger than the sum of its proper divisors (803675569).
1214351500127 is an equidigital number, since it uses as much as digits as its factorization.
1214351500127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 803675568.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 1214351500127 in words is "one trillion, two hundred fourteen billion, three hundred fifty-one million, five hundred thousand, one hundred twenty-seven".
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