Base | Representation |
---|---|
bin | 10110100111101011… |
… | …11000111000110101 |
3 | 1011100100011212000212 |
4 | 23103311320320311 |
5 | 144332334210223 |
6 | 5325013115205 |
7 | 606640516463 |
oct | 132365707065 |
9 | 34310155025 |
10 | 12144053813 |
11 | 5172002411 |
12 | 242b028b05 |
13 | 11b6c61078 |
14 | 832bd9833 |
15 | 4b1228278 |
hex | 2d3d78e35 |
12144053813 has 4 divisors (see below), whose sum is σ = 12783214560. Its totient is φ = 11504893068.
The previous prime is 12144053809. The next prime is 12144053849. The reversal of 12144053813 is 31835044121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12144053813 - 22 = 12144053809 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 12144053813.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12144053893) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319580345 + ... + 319580382.
It is an arithmetic number, because the mean of its divisors is an integer number (3195803640).
Almost surely, 212144053813 is an apocalyptic number.
It is an amenable number.
12144053813 is a deficient number, since it is larger than the sum of its proper divisors (639160747).
12144053813 is an equidigital number, since it uses as much as digits as its factorization.
12144053813 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 639160746.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 12144053813 its reverse (31835044121), we get a palindrome (43979097934).
The spelling of 12144053813 in words is "twelve billion, one hundred forty-four million, fifty-three thousand, eight hundred thirteen".
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