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12144243413993 is a prime number
BaseRepresentation
bin1011000010111000110101…
…0100001001001111101001
31120222222102012111202012212
42300232031110021033221
53042432402303221433
641454553255014505
72362251446550125
oct260561524111751
946888365452185
1012144243413993
113962387897759
12144177666a435
136a127444b022
142ddadaa04585
15160d76449d48
hexb0b8d5093e9

12144243413993 has 2 divisors, whose sum is σ = 12144243413994. Its totient is φ = 12144243413992.

The previous prime is 12144243413971. The next prime is 12144243414073. The reversal of 12144243413993 is 39931434244121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11723960896729 + 420282517264 = 3424027^2 + 648292^2 .

It is a cyclic number.

It is not a de Polignac number, because 12144243413993 - 210 = 12144243412969 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12144243413293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072121706996 + 6072121706997.

It is an arithmetic number, because the mean of its divisors is an integer number (6072121706997).

Almost surely, 212144243413993 is an apocalyptic number.

It is an amenable number.

12144243413993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12144243413993 is an equidigital number, since it uses as much as digits as its factorization.

12144243413993 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2239488, while the sum is 50.

The spelling of 12144243413993 in words is "twelve trillion, one hundred forty-four billion, two hundred forty-three million, four hundred thirteen thousand, nine hundred ninety-three".