12144410133 has 4 divisors (see below), whose sum is σ = 16192546848. Its totient is φ = 8096273420.

The previous prime is 12144410119. The next prime is 12144410143. The reversal of 12144410133 is 33101444121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12144410133 - 2²¹ = 12142312981 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12144410143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2024068353 + ... + 2024068358.

It is an arithmetic number, because the mean of its divisors is an integer number (4048136712).

Almost surely, 2^12144410133 is an apocalyptic number.

It is an amenable number.

12144410133 is a deficient number, since it is larger than the sum of its proper divisors (4048136715).

12144410133 is an equidigital number, since it uses as much as digits as its factorization.

12144410133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4048136714.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12144410133 its reverse (33101444121), we get a palindrome (45245854254).

The spelling of 12144410133 in words is "twelve billion, one hundred forty-four million, four hundred ten thousand, one hundred thirty-three".