1214441342213 has 4 divisors (see below), whose sum is σ = 1324845100608. Its totient is φ = 1104037583820.

The previous prime is 1214441342209. The next prime is 1214441342249. The reversal of 1214441342213 is 3122431444121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1214441342213 - 2² = 1214441342209 is a prime.

It is a super-2 number, since 2×1214441342213² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1214441342213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214441342273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55201879181 + ... + 55201879202.

It is an arithmetic number, because the mean of its divisors is an integer number (331211275152).

Almost surely, 2^{1214441342213} is an apocalyptic number.

It is an amenable number.

1214441342213 is a deficient number, since it is larger than the sum of its proper divisors (110403758395).

1214441342213 is a wasteful number, since it uses less digits than its factorization.

1214441342213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110403758394.

The product of its digits is 18432, while the sum is 32.

Adding to 1214441342213 its reverse (3122431444121), we get a palindrome (4336872786334).

The spelling of 1214441342213 in words is "one trillion, two hundred fourteen billion, four hundred forty-one million, three hundred forty-two thousand, two hundred thirteen".