1214442435053 has 4 divisors (see below), whose sum is σ = 1221152061948. Its totient is φ = 1207732808160.

The previous prime is 1214442435013. The next prime is 1214442435071. The reversal of 1214442435053 is 3505342444121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 441657272329 + 772785162724 = 664573^2 + 879082^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1214442435053 is a prime.

It is a super-2 number, since 2×1214442435053² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1214442434998 and 1214442435016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214442435013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3354813176 + ... + 3354813537.

It is an arithmetic number, because the mean of its divisors is an integer number (305288015487).

Almost surely, 2^{1214442435053} is an apocalyptic number.

It is an amenable number.

1214442435053 is a deficient number, since it is larger than the sum of its proper divisors (6709626895).

1214442435053 is an equidigital number, since it uses as much as digits as its factorization.

1214442435053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6709626894.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 1214442435053 its reverse (3505342444121), we get a palindrome (4719784879174).

The spelling of 1214442435053 in words is "one trillion, two hundred fourteen billion, four hundred forty-two million, four hundred thirty-five thousand, fifty-three".