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12144425633 is a prime number
BaseRepresentation
bin10110100111101110…
…10011101010100001
31011100100212202001222
423103313103222201
5144332433110013
65325025104425
7606643625504
oct132367235241
934310782058
1012144425633
1151722367aa
12242b188115
1311b7061392
14832c9513b
154b129d508
hex2d3dd3aa1

12144425633 has 2 divisors, whose sum is σ = 12144425634. Its totient is φ = 12144425632.

The previous prime is 12144425617. The next prime is 12144425651. The reversal of 12144425633 is 33652444121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11056943104 + 1087482529 = 105152^2 + 32977^2 .

It is a cyclic number.

It is not a de Polignac number, because 12144425633 - 24 = 12144425617 is a prime.

It is a super-3 number, since 3×121444256333 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12144425593 and 12144425602.

It is not a weakly prime, because it can be changed into another prime (12144425663) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6072212816 + 6072212817.

It is an arithmetic number, because the mean of its divisors is an integer number (6072212817).

Almost surely, 212144425633 is an apocalyptic number.

It is an amenable number.

12144425633 is a deficient number, since it is larger than the sum of its proper divisors (1).

12144425633 is an equidigital number, since it uses as much as digits as its factorization.

12144425633 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 35.

Adding to 12144425633 its reverse (33652444121), we get a palindrome (45796869754).

The spelling of 12144425633 in words is "twelve billion, one hundred forty-four million, four hundred twenty-five thousand, six hundred thirty-three".