Base | Representation |
---|---|
bin | 10001101011000011000… |
… | …010100011110111001011 |
3 | 11022002201022120212122111 |
4 | 101223003002203313023 |
5 | 124344144432141041 |
6 | 2325524554403151 |
7 | 153512164140055 |
oct | 21530302436713 |
9 | 4262638525574 |
10 | 1214453005771 |
11 | 429057074265 |
12 | 177451a304b7 |
13 | 8a6a3a06725 |
14 | 42acbc428d5 |
15 | 218cd9a2981 |
hex | 11ac30a3dcb |
1214453005771 has 2 divisors, whose sum is σ = 1214453005772. Its totient is φ = 1214453005770.
The previous prime is 1214453005763. The next prime is 1214453005793. The reversal of 1214453005771 is 1775003544121.
It is a weak prime.
It is an emirp because it is prime and its reverse (1775003544121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1214453005771 - 23 = 1214453005763 is a prime.
It is a super-2 number, since 2×12144530057712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1214453005471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607226502885 + 607226502886.
It is an arithmetic number, because the mean of its divisors is an integer number (607226502886).
Almost surely, 21214453005771 is an apocalyptic number.
1214453005771 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214453005771 is an equidigital number, since it uses as much as digits as its factorization.
1214453005771 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 117600, while the sum is 40.
Adding to 1214453005771 its reverse (1775003544121), we get a palindrome (2989456549892).
The spelling of 1214453005771 in words is "one trillion, two hundred fourteen billion, four hundred fifty-three million, five thousand, seven hundred seventy-one".
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