12145100704743 has 32 divisors (see below), whose sum is σ = 16240916378880. Its totient is φ = 8073060307200.

The previous prime is 12145100704739. The next prime is 12145100704829. The reversal of 12145100704743 is 34740700154121.

It is not a de Polignac number, because 12145100704743 - 2² = 12145100704739 is a prime.

It is a super-3 number, since 3×12145100704743³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12145100704703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5488069705 + ... + 5488071917.

It is an arithmetic number, because the mean of its divisors is an integer number (507528636840).

Almost surely, 2^{12145100704743} is an apocalyptic number.

12145100704743 is a deficient number, since it is larger than the sum of its proper divisors (4095815674137).

12145100704743 is a wasteful number, since it uses less digits than its factorization.

12145100704743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5919.

The product of its (nonzero) digits is 94080, while the sum is 39.

Adding to 12145100704743 its reverse (34740700154121), we get a palindrome (46885800858864).

The spelling of 12145100704743 in words is "twelve trillion, one hundred forty-five billion, one hundred million, seven hundred four thousand, seven hundred forty-three".