1214623433 has 2 divisors, whose sum is σ = 1214623434. Its totient is φ = 1214623432.

The previous prime is 1214623409. The next prime is 1214623439. The reversal of 1214623433 is 3343264121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 731810704 + 482812729 = 27052^2 + 21973^2 .

It is a cyclic number.

It is not a de Polignac number, because 1214623433 - 2⁸ = 1214623177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1214623396 and 1214623405.

It is not a weakly prime, because it can be changed into another prime (1214623439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607311716 + 607311717.

It is an arithmetic number, because the mean of its divisors is an integer number (607311717).

Almost surely, 2^1214623433 is an apocalyptic number.

It is an amenable number.

1214623433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214623433 is an equidigital number, since it uses as much as digits as its factorization.

1214623433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 29.

The square root of 1214623433 is about 34851.4480760843. The cubic root of 1214623433 is about 1066.9577405618.

Adding to 1214623433 its reverse (3343264121), we get a palindrome (4557887554).

The spelling of 1214623433 in words is "one billion, two hundred fourteen million, six hundred twenty-three thousand, four hundred thirty-three".