Base | Representation |
---|---|
bin | 111000100101010100… |
… | …0100110101001001001 |
3 | 102121122022211200012222 |
4 | 1301022220212221021 |
5 | 3442323334223223 |
6 | 131453235343425 |
7 | 11531106342446 |
oct | 1611250465111 |
9 | 377568750188 |
10 | 121511242313 |
11 | 47594a2390a |
12 | 1b671a51b75 |
13 | b5c63147a6 |
14 | 5c49d349cd |
15 | 32629c10c8 |
hex | 1c4aa26a49 |
121511242313 has 2 divisors, whose sum is σ = 121511242314. Its totient is φ = 121511242312.
The previous prime is 121511242301. The next prime is 121511242357. The reversal of 121511242313 is 313242115121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 120706215184 + 805027129 = 347428^2 + 28373^2 .
It is a cyclic number.
It is not a de Polignac number, because 121511242313 - 222 = 121507048009 is a prime.
It is a super-3 number, since 3×1215112423133 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (121511245313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60755621156 + 60755621157.
It is an arithmetic number, because the mean of its divisors is an integer number (60755621157).
Almost surely, 2121511242313 is an apocalyptic number.
It is an amenable number.
121511242313 is a deficient number, since it is larger than the sum of its proper divisors (1).
121511242313 is an equidigital number, since it uses as much as digits as its factorization.
121511242313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 121511242313 its reverse (313242115121), we get a palindrome (434753357434).
The spelling of 121511242313 in words is "one hundred twenty-one billion, five hundred eleven million, two hundred forty-two thousand, three hundred thirteen".
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