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121511242313 is a prime number
BaseRepresentation
bin111000100101010100…
…0100110101001001001
3102121122022211200012222
41301022220212221021
53442323334223223
6131453235343425
711531106342446
oct1611250465111
9377568750188
10121511242313
1147594a2390a
121b671a51b75
13b5c63147a6
145c49d349cd
1532629c10c8
hex1c4aa26a49

121511242313 has 2 divisors, whose sum is σ = 121511242314. Its totient is φ = 121511242312.

The previous prime is 121511242301. The next prime is 121511242357. The reversal of 121511242313 is 313242115121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120706215184 + 805027129 = 347428^2 + 28373^2 .

It is a cyclic number.

It is not a de Polignac number, because 121511242313 - 222 = 121507048009 is a prime.

It is a super-3 number, since 3×1215112423133 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (121511245313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60755621156 + 60755621157.

It is an arithmetic number, because the mean of its divisors is an integer number (60755621157).

Almost surely, 2121511242313 is an apocalyptic number.

It is an amenable number.

121511242313 is a deficient number, since it is larger than the sum of its proper divisors (1).

121511242313 is an equidigital number, since it uses as much as digits as its factorization.

121511242313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 26.

Adding to 121511242313 its reverse (313242115121), we get a palindrome (434753357434).

The spelling of 121511242313 in words is "one hundred twenty-one billion, five hundred eleven million, two hundred forty-two thousand, three hundred thirteen".