Base | Representation |
---|---|
bin | 10001101011101010011… |
… | …101101010101101100011 |
3 | 11022011102102011100201001 |
4 | 101223222131222231203 |
5 | 124402023243020024 |
6 | 2330114343052431 |
7 | 153534445115431 |
oct | 21535235525543 |
9 | 4264372140631 |
10 | 1215114423139 |
11 | 429366460991 |
12 | 1775b7441117 |
13 | 8a77aa57456 |
14 | 42b51a15d51 |
15 | 2191baa3244 |
hex | 11aea76ab63 |
1215114423139 has 2 divisors, whose sum is σ = 1215114423140. Its totient is φ = 1215114423138.
The previous prime is 1215114423073. The next prime is 1215114423143. The reversal of 1215114423139 is 9313244115121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1215114423139 - 27 = 1215114423011 is a prime.
It is a super-2 number, since 2×12151144231392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1215114423098 and 1215114423107.
It is not a weakly prime, because it can be changed into another prime (1215114423169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607557211569 + 607557211570.
It is an arithmetic number, because the mean of its divisors is an integer number (607557211570).
Almost surely, 21215114423139 is an apocalyptic number.
1215114423139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1215114423139 is an equidigital number, since it uses as much as digits as its factorization.
1215114423139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 25920, while the sum is 37.
The spelling of 1215114423139 in words is "one trillion, two hundred fifteen billion, one hundred fourteen million, four hundred twenty-three thousand, one hundred thirty-nine".
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