Base | Representation |
---|---|
bin | 1011000011010011111111… |
… | …0111100010101110011111 |
3 | 1121000200020022001011010121 |
4 | 2300310333313202232133 |
5 | 3043042320201131101 |
6 | 41502200533415411 |
7 | 2362630224551002 |
oct | 260647767425637 |
9 | 47020208034117 |
10 | 12151534005151 |
11 | 3965489179802 |
12 | 144307019a567 |
13 | 6a1b66a092a8 |
14 | 3001ccda5539 |
15 | 1611515150a1 |
hex | b0d3fde2b9f |
12151534005151 has 4 divisors (see below), whose sum is σ = 12157236275704. Its totient is φ = 12145831734600.
The previous prime is 12151534005119. The next prime is 12151534005157. The reversal of 12151534005151 is 15150043515121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12151534005151 - 25 = 12151534005119 is a prime.
It is a super-2 number, since 2×121515340051512 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12151534005157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2851132080 + ... + 2851136341.
It is an arithmetic number, because the mean of its divisors is an integer number (3039309068926).
Almost surely, 212151534005151 is an apocalyptic number.
12151534005151 is a deficient number, since it is larger than the sum of its proper divisors (5702270553).
12151534005151 is an equidigital number, since it uses as much as digits as its factorization.
12151534005151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5702270552.
The product of its (nonzero) digits is 15000, while the sum is 34.
The spelling of 12151534005151 in words is "twelve trillion, one hundred fifty-one billion, five hundred thirty-four million, five thousand, one hundred fifty-one".
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