Base | Representation |
---|---|
bin | 10110101000110000… |
… | …11100101010011010 |
3 | 1011100222020010020021 |
4 | 23110120130222122 |
5 | 144342144110432 |
6 | 5325535221054 |
7 | 610110521014 |
oct | 132430345232 |
9 | 34328203207 |
10 | 12153113242 |
11 | 517712a946 |
12 | 243207778a |
13 | 11b8ab378a |
14 | 8340b71b4 |
15 | 4b1e17697 |
hex | 2d461ca9a |
12153113242 has 4 divisors (see below), whose sum is σ = 18229669866. Its totient is φ = 6076556620.
The previous prime is 12153113237. The next prime is 12153113243. The reversal of 12153113242 is 24231135121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24231135121 = 83 ⋅291941387.
It can be written as a sum of positive squares in only one way, i.e., 7615878361 + 4537234881 = 87269^2 + 67359^2 .
It is a super-2 number, since 2×121531132422 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12153113243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3038278309 + ... + 3038278312.
Almost surely, 212153113242 is an apocalyptic number.
12153113242 is a deficient number, since it is larger than the sum of its proper divisors (6076556624).
12153113242 is an equidigital number, since it uses as much as digits as its factorization.
12153113242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6076556623.
The product of its digits is 1440, while the sum is 25.
Adding to 12153113242 its reverse (24231135121), we get a palindrome (36384248363).
The spelling of 12153113242 in words is "twelve billion, one hundred fifty-three million, one hundred thirteen thousand, two hundred forty-two".
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