1215545503433 has 2 divisors, whose sum is σ = 1215545503434. Its totient is φ = 1215545503432.

The previous prime is 1215545503421. The next prime is 1215545503553. The reversal of 1215545503433 is 3343055455121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1085403497929 + 130142005504 = 1041827^2 + 360752^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1215545503433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1215545503633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607772751716 + 607772751717.

It is an arithmetic number, because the mean of its divisors is an integer number (607772751717).

Almost surely, 2^{1215545503433} is an apocalyptic number.

It is an amenable number.

1215545503433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1215545503433 is an equidigital number, since it uses as much as digits as its factorization.

1215545503433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 1215545503433 in words is "one trillion, two hundred fifteen billion, five hundred forty-five million, five hundred three thousand, four hundred thirty-three".