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12155550768457 is a prime number
BaseRepresentation
bin1011000011100010111101…
…0010010001110101001001
31121001001121020021212111221
42300320233102101311021
53043124031444042312
641504103302522041
72363131610513125
oct260705722216511
947031536255457
1012155550768457
11396715a5724a8
1214439b1436321
136a2356c49b05
14300490640585
151612d8e9c207
hexb0e2f491d49

12155550768457 has 2 divisors, whose sum is σ = 12155550768458. Its totient is φ = 12155550768456.

The previous prime is 12155550768437. The next prime is 12155550768469. The reversal of 12155550768457 is 75486705555121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10417427580816 + 1738123187641 = 3227604^2 + 1318379^2 .

It is a cyclic number.

It is not a de Polignac number, because 12155550768457 - 235 = 12121191030089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12155550768395 and 12155550768404.

It is not a weakly prime, because it can be changed into another prime (12155550768437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6077775384228 + 6077775384229.

It is an arithmetic number, because the mean of its divisors is an integer number (6077775384229).

Almost surely, 212155550768457 is an apocalyptic number.

It is an amenable number.

12155550768457 is a deficient number, since it is larger than the sum of its proper divisors (1).

12155550768457 is an equidigital number, since it uses as much as digits as its factorization.

12155550768457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58800000, while the sum is 61.

The spelling of 12155550768457 in words is "twelve trillion, one hundred fifty-five billion, five hundred fifty million, seven hundred sixty-eight thousand, four hundred fifty-seven".