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121570364286113 is a prime number
BaseRepresentation
bin11011101001000101001110…
…011000001110010010100001
3120221110000100201020021010212
4123221011032120032102201
5111413302101224123423
61110320353201303505
734415111646320051
oct3351051630162241
9527400321207125
10121570364286113
113581077a341176
1211775199034b95
1352ab0615a6522
14220407385b561
15e0c4ce0bc578
hex6e914e60e4a1

121570364286113 has 2 divisors, whose sum is σ = 121570364286114. Its totient is φ = 121570364286112.

The previous prime is 121570364286083. The next prime is 121570364286181. The reversal of 121570364286113 is 311682463075121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95015842226449 + 26554522059664 = 9747607^2 + 5153108^2 .

It is an emirp because it is prime and its reverse (311682463075121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121570364286113 - 216 = 121570364220577 is a prime.

It is not a weakly prime, because it can be changed into another prime (121570364286013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60785182143056 + 60785182143057.

It is an arithmetic number, because the mean of its divisors is an integer number (60785182143057).

Almost surely, 2121570364286113 is an apocalyptic number.

It is an amenable number.

121570364286113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121570364286113 is an equidigital number, since it uses as much as digits as its factorization.

121570364286113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 121570364286113 in words is "one hundred twenty-one trillion, five hundred seventy billion, three hundred sixty-four million, two hundred eighty-six thousand, one hundred thirteen".