Base | Representation |
---|---|
bin | 100100001111110… |
… | …0011100000001001 |
3 | 10010202112221212122 |
4 | 1020133203200021 |
5 | 4442323401213 |
6 | 320404021025 |
7 | 42065540144 |
oct | 11037434011 |
9 | 3122487778 |
10 | 1216231433 |
11 | 57459274a |
12 | 29b391775 |
13 | 164c88491 |
14 | b775705b |
15 | 71b94d08 |
hex | 487e3809 |
1216231433 has 2 divisors, whose sum is σ = 1216231434. Its totient is φ = 1216231432.
The previous prime is 1216231427. The next prime is 1216231529. The reversal of 1216231433 is 3341326121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1151380624 + 64850809 = 33932^2 + 8053^2 .
It is a cyclic number.
It is not a de Polignac number, because 1216231433 - 24 = 1216231417 is a prime.
It is not a weakly prime, because it can be changed into another prime (1216239433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608115716 + 608115717.
It is an arithmetic number, because the mean of its divisors is an integer number (608115717).
Almost surely, 21216231433 is an apocalyptic number.
It is an amenable number.
1216231433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216231433 is an equidigital number, since it uses as much as digits as its factorization.
1216231433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 26.
The square root of 1216231433 is about 34874.5097886694. The cubic root of 1216231433 is about 1067.4283696888.
Adding to 1216231433 its reverse (3341326121), we get a palindrome (4557557554).
The spelling of 1216231433 in words is "one billion, two hundred sixteen million, two hundred thirty-one thousand, four hundred thirty-three".
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