Base | Representation |
---|---|
bin | 10001101100101101100… |
… | …101001010111100100011 |
3 | 11022021022220000010220012 |
4 | 101230231211022330203 |
5 | 124411330024314101 |
6 | 2330422210035135 |
7 | 153604400236403 |
oct | 21545545127443 |
9 | 4267286003805 |
10 | 1216240463651 |
11 | 429894041884 |
12 | 177870578aab |
13 | 8a8ca124b05 |
14 | 42c1b3b2803 |
15 | 2198587ebbb |
hex | 11b2d94af23 |
1216240463651 has 2 divisors, whose sum is σ = 1216240463652. Its totient is φ = 1216240463650.
The previous prime is 1216240463593. The next prime is 1216240463663. The reversal of 1216240463651 is 1563640426121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1216240463651 - 234 = 1199060594467 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1216240463599 and 1216240463608.
It is not a weakly prime, because it can be changed into another prime (1216240463051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 608120231825 + 608120231826.
It is an arithmetic number, because the mean of its divisors is an integer number (608120231826).
Almost surely, 21216240463651 is an apocalyptic number.
1216240463651 is a deficient number, since it is larger than the sum of its proper divisors (1).
1216240463651 is an equidigital number, since it uses as much as digits as its factorization.
1216240463651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 41.
Adding to 1216240463651 its reverse (1563640426121), we get a palindrome (2779880889772).
The spelling of 1216240463651 in words is "one trillion, two hundred sixteen billion, two hundred forty million, four hundred sixty-three thousand, six hundred fifty-one".
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