Base | Representation |
---|---|
bin | 1011000100010111110111… |
… | …1100010100101100101100 |
3 | 1121002102021011122121011220 |
4 | 2301011331330110230230 |
5 | 3043342124330034423 |
6 | 41514413003343340 |
7 | 2364143611253205 |
oct | 261057574245454 |
9 | 47072234577156 |
10 | 12169755314988 |
11 | 3972189679557 |
12 | 14466b6521b50 |
13 | 6a37aba4552b |
14 | 30103ad605ac |
15 | 16186b0369e3 |
hex | b117df14b2c |
12169755314988 has 12 divisors (see below), whose sum is σ = 28396095735000. Its totient is φ = 4056585104992.
The previous prime is 12169755314963. The next prime is 12169755315049. The reversal of 12169755314988 is 88941355796121.
It is a tau number, because it is divible by the number of its divisors (12).
It is a super-3 number, since 3×121697553149883 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 507073138113 + ... + 507073138136.
It is an arithmetic number, because the mean of its divisors is an integer number (2366341311250).
Almost surely, 212169755314988 is an apocalyptic number.
It is an amenable number.
12169755314988 is an abundant number, since it is smaller than the sum of its proper divisors (16226340420012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12169755314988 is a wasteful number, since it uses less digits than its factorization.
12169755314988 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1014146276256 (or 1014146276254 counting only the distinct ones).
The product of its digits is 130636800, while the sum is 69.
The spelling of 12169755314988 in words is "twelve trillion, one hundred sixty-nine billion, seven hundred fifty-five million, three hundred fourteen thousand, nine hundred eighty-eight".
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