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121701356809 is a prime number
BaseRepresentation
bin111000101010111110…
…1110101010100001001
3102122010120120111021121
41301111331311110021
53443221021404214
6131524150235241
711535605315224
oct1612575652411
9378116514247
10121701356809
114768227472a
121b705655b21
13b62681a386
145c672a25bb
153274526424
hex1c55f75509

121701356809 has 2 divisors, whose sum is σ = 121701356810. Its totient is φ = 121701356808.

The previous prime is 121701356767. The next prime is 121701356827. The reversal of 121701356809 is 908653107121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120688844409 + 1012512400 = 347403^2 + 31820^2 .

It is a cyclic number.

It is not a de Polignac number, because 121701356809 - 219 = 121700832521 is a prime.

It is a super-2 number, since 2×1217013568092 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121701356879) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60850678404 + 60850678405.

It is an arithmetic number, because the mean of its divisors is an integer number (60850678405).

Almost surely, 2121701356809 is an apocalyptic number.

It is an amenable number.

121701356809 is a deficient number, since it is larger than the sum of its proper divisors (1).

121701356809 is an equidigital number, since it uses as much as digits as its factorization.

121701356809 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90720, while the sum is 43.

The spelling of 121701356809 in words is "one hundred twenty-one billion, seven hundred one million, three hundred fifty-six thousand, eight hundred nine".