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121701924913 is a prime number
BaseRepresentation
bin111000101011000000…
…0000000000000110001
3102122010121122100120111
41301112000000000301
53443221143044123
6131524210341321
711535613202422
oct1612600000061
9378117570514
10121701924913
1147682622538
121b70588a841
13b626988b2a
145c673ad649
1532745d990d
hex1c56000031

121701924913 has 2 divisors, whose sum is σ = 121701924914. Its totient is φ = 121701924912.

The previous prime is 121701924901. The next prime is 121701924931. The reversal of 121701924913 is 319429107121.

Together with next prime (121701924931) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107385323809 + 14316601104 = 327697^2 + 119652^2 .

It is a cyclic number.

It is not a de Polignac number, because 121701924913 - 217 = 121701793841 is a prime.

It is a super-2 number, since 2×1217019249132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121701924413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60850962456 + 60850962457.

It is an arithmetic number, because the mean of its divisors is an integer number (60850962457).

Almost surely, 2121701924913 is an apocalyptic number.

It is an amenable number.

121701924913 is a deficient number, since it is larger than the sum of its proper divisors (1).

121701924913 is an equidigital number, since it uses as much as digits as its factorization.

121701924913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216, while the sum is 40.

The spelling of 121701924913 in words is "one hundred twenty-one billion, seven hundred one million, nine hundred twenty-four thousand, nine hundred thirteen".