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121804342255553 is a prime number
BaseRepresentation
bin11011101100011111001000…
…100011010101111111000001
3120222021101022001001122012212
4123230133020203111333001
5111431120243104134203
61111020050425231505
734441034102252336
oct3354371043257701
9528241261048185
10121804342255553
11358a0a27852751
12117b25b7932595
1352c713c167759
14221150c40498d
15e136254dd1d8
hex6ec7c88d5fc1

121804342255553 has 2 divisors, whose sum is σ = 121804342255554. Its totient is φ = 121804342255552.

The previous prime is 121804342255543. The next prime is 121804342255613. The reversal of 121804342255553 is 355552243408121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108386568126769 + 13417774128784 = 10410887^2 + 3663028^2 .

It is an emirp because it is prime and its reverse (355552243408121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121804342255553 - 216 = 121804342190017 is a prime.

It is not a weakly prime, because it can be changed into another prime (121804342255543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60902171127776 + 60902171127777.

It is an arithmetic number, because the mean of its divisors is an integer number (60902171127777).

Almost surely, 2121804342255553 is an apocalyptic number.

It is an amenable number.

121804342255553 is a deficient number, since it is larger than the sum of its proper divisors (1).

121804342255553 is an equidigital number, since it uses as much as digits as its factorization.

121804342255553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760000, while the sum is 50.

The spelling of 121804342255553 in words is "one hundred twenty-one trillion, eight hundred four billion, three hundred forty-two million, two hundred fifty-five thousand, five hundred fifty-three".