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12195840471833 is a prime number
BaseRepresentation
bin1011000101111001000010…
…1111010011001100011001
31121011220121002110212100002
42301132100233103030121
53044304040130044313
641534405231022345
72366056203400154
oct261362057231431
947156532425302
1012195840471833
113982255001a17
12144b77636a9b5
136a60a8033595
143023d34a0c9b
1516239610c058
hexb1790bd3319

12195840471833 has 2 divisors, whose sum is σ = 12195840471834. Its totient is φ = 12195840471832.

The previous prime is 12195840471797. The next prime is 12195840471847. The reversal of 12195840471833 is 33817404859121.

12195840471833 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12092122981129 + 103717490704 = 3477373^2 + 322052^2 .

It is a cyclic number.

It is not a de Polignac number, because 12195840471833 - 26 = 12195840471769 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12195840471853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6097920235916 + 6097920235917.

It is an arithmetic number, because the mean of its divisors is an integer number (6097920235917).

Almost surely, 212195840471833 is an apocalyptic number.

It is an amenable number.

12195840471833 is a deficient number, since it is larger than the sum of its proper divisors (1).

12195840471833 is an equidigital number, since it uses as much as digits as its factorization.

12195840471833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 56.

The spelling of 12195840471833 in words is "twelve trillion, one hundred ninety-five billion, eight hundred forty million, four hundred seventy-one thousand, eight hundred thirty-three".