Base | Representation |
---|---|
bin | 11011101111010110010010… |
… | …010001100001110011001011 |
3 | 120222222011220110111210201001 |
4 | 123233112102101201303023 |
5 | 111442331022012030212 |
6 | 1111250252525435431 |
7 | 34461165341405512 |
oct | 3357262221416313 |
9 | 528864813453631 |
10 | 122001000111307 |
11 | 35967374004469 |
12 | 1182474010bb77 |
13 | 530c84cc39a85 |
14 | 221ac46699679 |
15 | e187d5337657 |
hex | 6ef592461ccb |
122001000111307 has 2 divisors, whose sum is σ = 122001000111308. Its totient is φ = 122001000111306.
The previous prime is 122001000111203. The next prime is 122001000111329. The reversal of 122001000111307 is 703111000100221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122001000111307 is a prime.
It is not a weakly prime, because it can be changed into another prime (122001000115307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61000500055653 + 61000500055654.
It is an arithmetic number, because the mean of its divisors is an integer number (61000500055654).
Almost surely, 2122001000111307 is an apocalyptic number.
122001000111307 is a deficient number, since it is larger than the sum of its proper divisors (1).
122001000111307 is an equidigital number, since it uses as much as digits as its factorization.
122001000111307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 122001000111307 its reverse (703111000100221), we get a palindrome (825112000211528).
The spelling of 122001000111307 in words is "one hundred twenty-two trillion, one billion, one hundred eleven thousand, three hundred seven".
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