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122001020100122 = 261000510050061
BaseRepresentation
bin11011101111010110010011…
…011101110001111000011010
3120222222011221212010100012112
4123233112103131301320122
5111442331042121200442
61111250254522112322
734461166003330112
oct3357262335617032
9528864855110175
10122001020100122
1135967384317349
121182474694b6a2
13530c854118087
14221ac491c0042
15e187d6e85082
hex6ef593771e1a

122001020100122 has 4 divisors (see below), whose sum is σ = 183001530150186. Its totient is φ = 61000510050060.

The previous prime is 122001020100109. The next prime is 122001020100137. The reversal of 122001020100122 is 221001020100221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 89708725017961 + 32292295082161 = 9471469^2 + 5682631^2 .

It is a junction number, because it is equal to n+sod(n) for n = 122001020100097 and 122001020100106.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30500255025029 + ... + 30500255025032.

Almost surely, 2122001020100122 is an apocalyptic number.

122001020100122 is a deficient number, since it is larger than the sum of its proper divisors (61000510050064).

122001020100122 is an equidigital number, since it uses as much as digits as its factorization.

122001020100122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61000510050063.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 122001020100122 its reverse (221001020100221), we get a palindrome (343002040200343).

Subtracting 122001020100122 from its reverse (221001020100221), we obtain a palindrome (99000000000099).

The spelling of 122001020100122 in words is "one hundred twenty-two trillion, one billion, twenty million, one hundred thousand, one hundred twenty-two".

Divisors: 1 2 61000510050061 122001020100122