Base | Representation |
---|---|
bin | 11011101111010110011110… |
… | …010100100000110001011011 |
3 | 120222222012102112210222212202 |
4 | 123233112132110200301123 |
5 | 111442331430232020443 |
6 | 1111250324545400415 |
7 | 34461203344325162 |
oct | 3357263624406133 |
9 | 528865375728782 |
10 | 122001202220123 |
11 | 359674680a7846 |
12 | 1182479793910b |
13 | 530c882a81ba5 |
14 | 221ac6546a3d9 |
15 | e187e7e5b7b8 |
hex | 6ef59e520c5b |
122001202220123 has 2 divisors, whose sum is σ = 122001202220124. Its totient is φ = 122001202220122.
The previous prime is 122001202219999. The next prime is 122001202220159. The reversal of 122001202220123 is 321022202100221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122001202220123 is a prime.
It is a super-2 number, since 2×1220012022201232 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122001202220095 and 122001202220104.
It is not a weakly prime, because it can be changed into another prime (122001202223123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61000601110061 + 61000601110062.
It is an arithmetic number, because the mean of its divisors is an integer number (61000601110062).
Almost surely, 2122001202220123 is an apocalyptic number.
122001202220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
122001202220123 is an equidigital number, since it uses as much as digits as its factorization.
122001202220123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 122001202220123 its reverse (321022202100221), we get a palindrome (443023404320344).
The spelling of 122001202220123 in words is "one hundred twenty-two trillion, one billion, two hundred two million, two hundred twenty thousand, one hundred twenty-three".
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