Base | Representation |
---|---|
bin | 1011000110001100010001… |
… | …0001010101101100111001 |
3 | 1121012101220200001001211111 |
4 | 2301203010101111230321 |
5 | 3044400122000002223 |
6 | 41541021221400321 |
7 | 2366331103561225 |
oct | 261430421255471 |
9 | 47171820031744 |
10 | 12201000000313 |
11 | 398446246a043 |
12 | 14507762690a1 |
13 | 6a671ac49107 |
14 | 30276280b785 |
15 | 16259907630d |
hex | b18c4455b39 |
12201000000313 has 2 divisors, whose sum is σ = 12201000000314. Its totient is φ = 12201000000312.
The previous prime is 12201000000281. The next prime is 12201000000323. The reversal of 12201000000313 is 31300000010221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9134708327424 + 3066291672889 = 3022368^2 + 1751083^2 .
It is a cyclic number.
It is not a de Polignac number, because 12201000000313 - 25 = 12201000000281 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12201000000293 and 12201000000302.
It is not a weakly prime, because it can be changed into another prime (12201000000323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100500000156 + 6100500000157.
It is an arithmetic number, because the mean of its divisors is an integer number (6100500000157).
Almost surely, 212201000000313 is an apocalyptic number.
It is an amenable number.
12201000000313 is a deficient number, since it is larger than the sum of its proper divisors (1).
12201000000313 is an equidigital number, since it uses as much as digits as its factorization.
12201000000313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12201000000313 its reverse (31300000010221), we get a palindrome (43501000010534).
The spelling of 12201000000313 in words is "twelve trillion, two hundred one billion, three hundred thirteen", and thus it is an aban number.
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