Base | Representation |
---|---|
bin | 111000110100001100… |
… | …0110000001001101001 |
3 | 102122221010002200112212 |
4 | 1301220120300021221 |
5 | 3444334130402213 |
6 | 132014550214505 |
7 | 11546350213622 |
oct | 1615030601151 |
9 | 378833080485 |
10 | 122010403433 |
11 | 47820767a66 |
12 | 1b791054435 |
13 | b675864ab9 |
14 | 5c9634ca49 |
15 | 32917209a8 |
hex | 1c68630269 |
122010403433 has 2 divisors, whose sum is σ = 122010403434. Its totient is φ = 122010403432.
The previous prime is 122010403337. The next prime is 122010403451. The reversal of 122010403433 is 334304010221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116589468304 + 5420935129 = 341452^2 + 73627^2 .
It is a cyclic number.
It is not a de Polignac number, because 122010403433 - 214 = 122010387049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122010403399 and 122010403408.
It is not a weakly prime, because it can be changed into another prime (122010403483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61005201716 + 61005201717.
It is an arithmetic number, because the mean of its divisors is an integer number (61005201717).
Almost surely, 2122010403433 is an apocalyptic number.
It is an amenable number.
122010403433 is a deficient number, since it is larger than the sum of its proper divisors (1).
122010403433 is an equidigital number, since it uses as much as digits as its factorization.
122010403433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 122010403433 its reverse (334304010221), we get a palindrome (456314413654).
The spelling of 122010403433 in words is "one hundred twenty-two billion, ten million, four hundred three thousand, four hundred thirty-three".
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