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12201112220993 is a prime number
BaseRepresentation
bin1011000110001100101011…
…1101011011010101000001
31121012102012111012110122222
42301203022331123111001
53044400334212032433
641541040310540425
72366333635462223
oct261431275332501
947172174173588
1012201112220993
11398450a848103
1214507a7967715
136a673827b197
143027736a0413
151625a3d41b98
hexb18caf5b541

12201112220993 has 2 divisors, whose sum is σ = 12201112220994. Its totient is φ = 12201112220992.

The previous prime is 12201112220971. The next prime is 12201112221007. The reversal of 12201112220993 is 39902221110221.

12201112220993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11979580089409 + 221532131584 = 3461153^2 + 470672^2 .

It is a cyclic number.

It is not a de Polignac number, because 12201112220993 - 214 = 12201112204609 is a prime.

It is not a weakly prime, because it can be changed into another prime (12201112220933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100556110496 + 6100556110497.

It is an arithmetic number, because the mean of its divisors is an integer number (6100556110497).

Almost surely, 212201112220993 is an apocalyptic number.

It is an amenable number.

12201112220993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201112220993 is an equidigital number, since it uses as much as digits as its factorization.

12201112220993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 35.

The spelling of 12201112220993 in words is "twelve trillion, two hundred one billion, one hundred twelve million, two hundred twenty thousand, nine hundred ninety-three".