Base | Representation |
---|---|
bin | 1011000110001100101101… |
… | …1011001001001101011111 |
3 | 1121012102020000212020200120 |
4 | 2301203023123021031133 |
5 | 3044400343210323403 |
6 | 41541041145530023 |
7 | 2366334061626012 |
oct | 261431333111537 |
9 | 47172200766616 |
10 | 12201120011103 |
11 | 3984514188a11 |
12 | 14507aa4a3913 |
13 | 6a6739a77c0a |
14 | 30277472b379 |
15 | 1625a487ee53 |
hex | b18cb6c935f |
12201120011103 has 4 divisors (see below), whose sum is σ = 16268160014808. Its totient is φ = 8134080007400.
The previous prime is 12201120011083. The next prime is 12201120011107. The reversal of 12201120011103 is 30111002110221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12201120011103 - 212 = 12201120007007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12201120011107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2033520001848 + ... + 2033520001853.
It is an arithmetic number, because the mean of its divisors is an integer number (4067040003702).
Almost surely, 212201120011103 is an apocalyptic number.
12201120011103 is a deficient number, since it is larger than the sum of its proper divisors (4067040003705).
12201120011103 is an equidigital number, since it uses as much as digits as its factorization.
12201120011103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4067040003704.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 12201120011103 its reverse (30111002110221), we get a palindrome (42312122121324).
The spelling of 12201120011103 in words is "twelve trillion, two hundred one billion, one hundred twenty million, eleven thousand, one hundred three".
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