Base | Representation |
---|---|
bin | 10001110000010100011… |
… | …111001110001110010011 |
3 | 11022122022212120120220201 |
4 | 101300110133032032103 |
5 | 124442243244103412 |
6 | 2332302434520031 |
7 | 154102400426332 |
oct | 21602437161623 |
9 | 4278285516821 |
10 | 1220114441107 |
11 | 4304a1880441 |
12 | 178571a36017 |
13 | 8b0968c1273 |
14 | 430a7abdd19 |
15 | 21b10a0ee57 |
hex | 11c147ce393 |
1220114441107 has 2 divisors, whose sum is σ = 1220114441108. Its totient is φ = 1220114441106.
The previous prime is 1220114441099. The next prime is 1220114441113. The reversal of 1220114441107 is 7011444110221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1220114441107 - 23 = 1220114441099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1220114441177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610057220553 + 610057220554.
It is an arithmetic number, because the mean of its divisors is an integer number (610057220554).
Almost surely, 21220114441107 is an apocalyptic number.
1220114441107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220114441107 is an equidigital number, since it uses as much as digits as its factorization.
1220114441107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1792, while the sum is 28.
Adding to 1220114441107 its reverse (7011444110221), we get a palindrome (8231558551328).
The spelling of 1220114441107 in words is "one trillion, two hundred twenty billion, one hundred fourteen million, four hundred forty-one thousand, one hundred seven".
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