Base | Representation |
---|---|
bin | 10001110000010100111… |
… | …001000101010001000011 |
3 | 11022122100100100000000212 |
4 | 101300110321011101003 |
5 | 124442302013021123 |
6 | 2332303240104335 |
7 | 154102512152336 |
oct | 21602471052103 |
9 | 4278310300025 |
10 | 1220121220163 |
11 | 4304a569066a |
12 | 1785741650ab |
13 | 8b098125a41 |
14 | 430a896661d |
15 | 21b113ed878 |
hex | 11c14e45443 |
1220121220163 has 2 divisors, whose sum is σ = 1220121220164. Its totient is φ = 1220121220162.
The previous prime is 1220121220159. The next prime is 1220121220189. The reversal of 1220121220163 is 3610221210221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1220121220163 - 22 = 1220121220159 is a prime.
It is a super-3 number, since 3×12201212201633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1220121220463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610060610081 + 610060610082.
It is an arithmetic number, because the mean of its divisors is an integer number (610060610082).
Almost surely, 21220121220163 is an apocalyptic number.
1220121220163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1220121220163 is an equidigital number, since it uses as much as digits as its factorization.
1220121220163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1220121220163 its reverse (3610221210221), we get a palindrome (4830342430384).
The spelling of 1220121220163 in words is "one trillion, two hundred twenty billion, one hundred twenty-one million, two hundred twenty thousand, one hundred sixty-three".
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