Base | Representation |
---|---|
bin | 10001110000010101000… |
… | …000011010010000010111 |
3 | 11022122100110221121010021 |
4 | 101300111000122100113 |
5 | 124442303011004033 |
6 | 2332303345210011 |
7 | 154102534403014 |
oct | 21602500322027 |
9 | 4278313847107 |
10 | 1220123141143 |
11 | 4304a6782955 |
12 | 178574930907 |
13 | 8b09864920a |
14 | 430a8d0670b |
15 | 21b1167cb2d |
hex | 11c1501a417 |
1220123141143 has 16 divisors (see below), whose sum is σ = 1304048401920. Its totient is φ = 1137598156800.
The previous prime is 1220123141137. The next prime is 1220123141161. The reversal of 1220123141143 is 3411413210221.
It is a cyclic number.
It is not a de Polignac number, because 1220123141143 - 233 = 1211533206551 is a prime.
It is a super-2 number, since 2×12201231411432 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1220123141843) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2923 + ... + 1562131.
It is an arithmetic number, because the mean of its divisors is an integer number (81503025120).
Almost surely, 21220123141143 is an apocalyptic number.
1220123141143 is a deficient number, since it is larger than the sum of its proper divisors (83925260777).
1220123141143 is a wasteful number, since it uses less digits than its factorization.
1220123141143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1559658.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1220123141143 its reverse (3411413210221), we get a palindrome (4631536351364).
The spelling of 1220123141143 in words is "one trillion, two hundred twenty billion, one hundred twenty-three million, one hundred forty-one thousand, one hundred forty-three".
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