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122013001110000 = 24354711213431857
BaseRepresentation
bin11011101111100001011101…
…100101101101000111110000
3121000000022212211111201000010
4123233201131211231013300
5111443030111241010000
61111255555432454520
734462101624252060
oct3357413545550760
9530008784451003
10122013001110000
1135971472288400
1211826b2b24a440
135310a13361030
14221b6644973a0
15e18c88c03d50
hex6ef85d96d1f0

122013001110000 has 2400 divisors, whose sum is σ = 534703980754944. Its totient is φ = 23321548800000.

The previous prime is 122013001109977. The next prime is 122013001110001. The reversal of 122013001110000 is 11100310221.

It is a super-2 number, since 2×1220130011100002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122013001110001) by changing a digit.

It is a polite number, since it can be written in 479 ways as a sum of consecutive naturals, for example, 142372229572 + ... + 142372230428.

Almost surely, 2122013001110000 is an apocalyptic number.

122013001110000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 122013001110000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (267351990377472).

122013001110000 is an abundant number, since it is smaller than the sum of its proper divisors (412690979644944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122013001110000 is a wasteful number, since it uses less digits than its factorization.

122013001110000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1361 (or 1329 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 122013001110000 its reverse (11100310221), we get a palindrome (122024101420221).

The spelling of 122013001110000 in words is "one hundred twenty-two trillion, thirteen billion, one million, one hundred ten thousand".