Search a number
-
+
122013200331000 = 2332531137109305593
BaseRepresentation
bin11011101111100001101001…
…011101101011000011111000
3121000000100101201101011211200
4123233201221131223003320
5111443031013241043000
61111300031310454200
734462106563513236
oct3357415135530370
9530010351334750
10122013200331000
1135971564789060
1211826b85b04360
135310a45704894
14221b682b15956
15e18c9b457500
hex6ef86976b0f8

122013200331000 has 768 divisors, whose sum is σ = 466295861116800. Its totient is φ = 28515400704000.

The previous prime is 122013200330977. The next prime is 122013200331053. The reversal of 122013200331000 is 133002310221.

122013200331000 is a `hidden beast` number, since 1 + 220 + 132 + 0 + 0 + 3 + 310 + 0 + 0 = 666.

It is a super-2 number, since 2×1220132003310002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 399114204 + ... + 399419796.

Almost surely, 2122013200331000 is an apocalyptic number.

122013200331000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 122013200331000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233147930558400).

122013200331000 is an abundant number, since it is smaller than the sum of its proper divisors (344282660785800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

122013200331000 is a wasteful number, since it uses less digits than its factorization.

122013200331000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305777 (or 305760 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 122013200331000 its reverse (133002310221), we get a palindrome (122146202641221).

The spelling of 122013200331000 in words is "one hundred twenty-two trillion, thirteen billion, two hundred million, three hundred thirty-one thousand".