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12201321132000 = 25325371113379151
BaseRepresentation
bin1011000110001101011101…
…1010010110111111100000
31121012102202001022020200200
42301203113122112333200
53044401301202211000
641541113132345200
72366342053262220
oct261432732267740
947172661266620
1012201321132000
113984607767030
121450845915200
136a676c635470
14302793322080
151625b735b500
hexb18d7696fe0

12201321132000 has 2304 divisors, whose sum is σ = 59718291849216. Its totient is φ = 2276812800000.

The previous prime is 12201321131983. The next prime is 12201321132043. The reversal of 12201321132000 is 23112310221.

12201321132000 is a `hidden beast` number, since 1 + 2 + 20 + 1 + 321 + 1 + 320 + 0 + 0 = 666.

It is a super-2 number, since 2×122013211320002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 1333327425 + ... + 1333336575.

It is an arithmetic number, because the mean of its divisors is an integer number (25919397504).

Almost surely, 212201321132000 is an apocalyptic number.

12201321132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12201321132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29859145924608).

12201321132000 is an abundant number, since it is smaller than the sum of its proper divisors (47516970717216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12201321132000 is a wasteful number, since it uses less digits than its factorization.

12201321132000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9250 (or 9229 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12201321132000 its reverse (23112310221), we get a palindrome (12224433442221).

It can be divided in two parts, 12201321 and 132000, that added together give a palindrome (12333321).

The spelling of 12201321132000 in words is "twelve trillion, two hundred one billion, three hundred twenty-one million, one hundred thirty-two thousand".