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122013311323 is a prime number
BaseRepresentation
bin111000110100010001…
…1110110000101011011
3102122221022120102102111
41301220203312011123
53444340401430243
6132015132413151
711546414014501
oct1615043660533
9378838512374
10122013311323
1147822373782
121b7920171b7
13b676342547
145c968a8671
153291ae739d
hex1c688f615b

122013311323 has 2 divisors, whose sum is σ = 122013311324. Its totient is φ = 122013311322.

The previous prime is 122013311263. The next prime is 122013311341. The reversal of 122013311323 is 323113310221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122013311323 is a prime.

It is a super-3 number, since 3×1220133113233 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 122013311294 and 122013311303.

It is not a weakly prime, because it can be changed into another prime (122013311423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61006655661 + 61006655662.

It is an arithmetic number, because the mean of its divisors is an integer number (61006655662).

Almost surely, 2122013311323 is an apocalyptic number.

122013311323 is a deficient number, since it is larger than the sum of its proper divisors (1).

122013311323 is an equidigital number, since it uses as much as digits as its factorization.

122013311323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 122013311323 its reverse (323113310221), we get a palindrome (445126621544).

The spelling of 122013311323 in words is "one hundred twenty-two billion, thirteen million, three hundred eleven thousand, three hundred twenty-three".