Base | Representation |
---|---|
bin | 10001110000010110000… |
… | …001100101001001011001 |
3 | 11022122101200002112220220 |
4 | 101300112001211021121 |
5 | 124442321344200423 |
6 | 2332305155310253 |
7 | 154103132535345 |
oct | 21602601451131 |
9 | 4278350075826 |
10 | 1220140225113 |
11 | 430505391337 |
12 | 17857a5ab389 |
13 | 8b09c04b284 |
14 | 430ab2b2625 |
15 | 21b12e049e3 |
hex | 11c16065259 |
1220140225113 has 4 divisors (see below), whose sum is σ = 1626853633488. Its totient is φ = 813426816740.
The previous prime is 1220140225099. The next prime is 1220140225121. The reversal of 1220140225113 is 3115220410221.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1220140225113 - 28 = 1220140224857 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1220140220113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203356704183 + ... + 203356704188.
It is an arithmetic number, because the mean of its divisors is an integer number (406713408372).
Almost surely, 21220140225113 is an apocalyptic number.
It is an amenable number.
1220140225113 is a deficient number, since it is larger than the sum of its proper divisors (406713408375).
1220140225113 is an equidigital number, since it uses as much as digits as its factorization.
1220140225113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 406713408374.
The product of its (nonzero) digits is 960, while the sum is 24.
Adding to 1220140225113 its reverse (3115220410221), we get a palindrome (4335360635334).
The spelling of 1220140225113 in words is "one trillion, two hundred twenty billion, one hundred forty million, two hundred twenty-five thousand, one hundred thirteen".
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