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1220140225113 = 3406713408371
BaseRepresentation
bin10001110000010110000…
…001100101001001011001
311022122101200002112220220
4101300112001211021121
5124442321344200423
62332305155310253
7154103132535345
oct21602601451131
94278350075826
101220140225113
11430505391337
1217857a5ab389
138b09c04b284
14430ab2b2625
1521b12e049e3
hex11c16065259

1220140225113 has 4 divisors (see below), whose sum is σ = 1626853633488. Its totient is φ = 813426816740.

The previous prime is 1220140225099. The next prime is 1220140225121. The reversal of 1220140225113 is 3115220410221.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1220140225113 - 28 = 1220140224857 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1220140220113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203356704183 + ... + 203356704188.

It is an arithmetic number, because the mean of its divisors is an integer number (406713408372).

Almost surely, 21220140225113 is an apocalyptic number.

It is an amenable number.

1220140225113 is a deficient number, since it is larger than the sum of its proper divisors (406713408375).

1220140225113 is an equidigital number, since it uses as much as digits as its factorization.

1220140225113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 406713408374.

The product of its (nonzero) digits is 960, while the sum is 24.

Adding to 1220140225113 its reverse (3115220410221), we get a palindrome (4335360635334).

The spelling of 1220140225113 in words is "one trillion, two hundred twenty billion, one hundred forty million, two hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 3 406713408371 1220140225113