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1220143433 is a prime number
BaseRepresentation
bin100100010111001…
…1110100101001001
310011000220201010112
41020232132211021
54444324042213
6321023524105
742144022325
oct11056364511
93130821115
101220143433
11576814903
122a0759635
13165a27c82
14b8094985
15721b8ea8
hex48b9e949

1220143433 has 2 divisors, whose sum is σ = 1220143434. Its totient is φ = 1220143432.

The previous prime is 1220143429. The next prime is 1220143451. The reversal of 1220143433 is 3343410221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1037677369 + 182466064 = 32213^2 + 13508^2 .

It is a cyclic number.

It is not a de Polignac number, because 1220143433 - 22 = 1220143429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1220143399 and 1220143408.

It is not a weakly prime, because it can be changed into another prime (1220143033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 610071716 + 610071717.

It is an arithmetic number, because the mean of its divisors is an integer number (610071717).

Almost surely, 21220143433 is an apocalyptic number.

It is an amenable number.

1220143433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1220143433 is an equidigital number, since it uses as much as digits as its factorization.

1220143433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1220143433 is about 34930.5515702229. The cubic root of 1220143433 is about 1068.5716034874.

Adding to 1220143433 its reverse (3343410221), we get a palindrome (4563553654).

The spelling of 1220143433 in words is "one billion, two hundred twenty million, one hundred forty-three thousand, four hundred thirty-three".