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12201983737 is a prime number
BaseRepresentation
bin10110101110100101…
…10111111011111001
31011111101011222221121
423113102313323321
5144442201434422
65334442505241
7611243102416
oct132722677371
934441158847
1012201983737
1151a1779a89
122446505221
1311c5c64a28
1483a79910d
154b636c8c7
hex2d74b7ef9

12201983737 has 2 divisors, whose sum is σ = 12201983738. Its totient is φ = 12201983736.

The previous prime is 12201983611. The next prime is 12201983797. The reversal of 12201983737 is 73738910221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12084824761 + 117158976 = 109931^2 + 10824^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12201983737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12201983693 and 12201983702.

It is not a weakly prime, because it can be changed into another prime (12201983797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6100991868 + 6100991869.

It is an arithmetic number, because the mean of its divisors is an integer number (6100991869).

Almost surely, 212201983737 is an apocalyptic number.

It is an amenable number.

12201983737 is a deficient number, since it is larger than the sum of its proper divisors (1).

12201983737 is an equidigital number, since it uses as much as digits as its factorization.

12201983737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 127008, while the sum is 43.

The spelling of 12201983737 in words is "twelve billion, two hundred one million, nine hundred eighty-three thousand, seven hundred thirty-seven".