Base | Representation |
---|---|
bin | 1011000110010000011001… |
… | …1111011110000111011011 |
3 | 1121012111210002120202022222 |
4 | 2301210012133132013123 |
5 | 3044404410404013201 |
6 | 41541323350134255 |
7 | 2366400454122356 |
oct | 261440637360733 |
9 | 47174702522288 |
10 | 12202111001051 |
11 | 3984982608374 |
12 | 1450a2635138b |
13 | 6a686717bcba |
14 | 30282a1b129d |
15 | 16261188191b |
hex | b19067de1db |
12202111001051 has 2 divisors, whose sum is σ = 12202111001052. Its totient is φ = 12202111001050.
The previous prime is 12202111001021. The next prime is 12202111001131. The reversal of 12202111001051 is 15010011120221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12202111001051 - 214 = 12202110984667 is a prime.
It is not a weakly prime, because it can be changed into another prime (12202111001021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101055500525 + 6101055500526.
It is an arithmetic number, because the mean of its divisors is an integer number (6101055500526).
Almost surely, 212202111001051 is an apocalyptic number.
12202111001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12202111001051 is an equidigital number, since it uses as much as digits as its factorization.
12202111001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 12202111001051 its reverse (15010011120221), we get a palindrome (27212122121272).
The spelling of 12202111001051 in words is "twelve trillion, two hundred two billion, one hundred eleven million, one thousand, fifty-one".
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