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1220220134143 = 1443784520339
BaseRepresentation
bin10001110000011010110…
…010011010001011111111
311022122121020110100111121
4101300122302122023333
5124443002323243033
62332321132131411
7154105123002313
oct21603262321377
94278536410447
101220220134143
1143054650015a
121785a1306b67
138b0b277911a
14430b7b53b43
1521b19e3b62d
hex11c1ac9a2ff

1220220134143 has 4 divisors (see below), whose sum is σ = 1220304668920. Its totient is φ = 1220135599368.

The previous prime is 1220220134131. The next prime is 1220220134197. The reversal of 1220220134143 is 3414310220221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1220220134143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1220220134113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42245733 + ... + 42274606.

It is an arithmetic number, because the mean of its divisors is an integer number (305076167230).

Almost surely, 21220220134143 is an apocalyptic number.

1220220134143 is a deficient number, since it is larger than the sum of its proper divisors (84534777).

1220220134143 is an equidigital number, since it uses as much as digits as its factorization.

1220220134143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84534776.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1220220134143 its reverse (3414310220221), we get a palindrome (4634530354364).

The spelling of 1220220134143 in words is "one trillion, two hundred twenty billion, two hundred twenty million, one hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 14437 84520339 1220220134143