Base | Representation |
---|---|
bin | 1011000110010000110010… |
… | …1000110110101011011011 |
3 | 1121012112001021121221202202 |
4 | 2301210030220312223123 |
5 | 3044410113303434001 |
6 | 41541341512320415 |
7 | 2366403145503164 |
oct | 261441450665333 |
9 | 47175037557682 |
10 | 12202214124251 |
11 | 3984a25842358 |
12 | 1450a549a310b |
13 | 6a6882647248 |
14 | 302839b7676b |
15 | 16261a95196b |
hex | b190ca36adb |
12202214124251 has 2 divisors, whose sum is σ = 12202214124252. Its totient is φ = 12202214124250.
The previous prime is 12202214124119. The next prime is 12202214124277. The reversal of 12202214124251 is 15242141220221.
12202214124251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12202214124251 is a prime.
It is a super-2 number, since 2×122022141242512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12202214124851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101107062125 + 6101107062126.
It is an arithmetic number, because the mean of its divisors is an integer number (6101107062126).
Almost surely, 212202214124251 is an apocalyptic number.
12202214124251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12202214124251 is an equidigital number, since it uses as much as digits as its factorization.
12202214124251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5120, while the sum is 29.
Adding to 12202214124251 its reverse (15242141220221), we get a palindrome (27444355344472).
The spelling of 12202214124251 in words is "twelve trillion, two hundred two billion, two hundred fourteen million, one hundred twenty-four thousand, two hundred fifty-one".
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