Base | Representation |
---|---|
bin | 10110101110100111… |
… | …10100000011101001 |
3 | 1011111101122111202012 |
4 | 23113103310003221 |
5 | 144442232324433 |
6 | 5334452045305 |
7 | 611245146362 |
oct | 132723640351 |
9 | 34441574665 |
10 | 12202229993 |
11 | 51a1927aa8 |
12 | 2446603835 |
13 | 11c601cb45 |
14 | 83a820b69 |
15 | 4b63ba848 |
hex | 2d74f40e9 |
12202229993 has 2 divisors, whose sum is σ = 12202229994. Its totient is φ = 12202229992.
The previous prime is 12202229987. The next prime is 12202230017. The reversal of 12202229993 is 39992220221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7250011609 + 4952218384 = 85147^2 + 70372^2 .
It is a cyclic number.
It is not a de Polignac number, because 12202229993 - 26 = 12202229929 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12202229993.
It is not a weakly prime, because it can be changed into another prime (12202229983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101114996 + 6101114997.
It is an arithmetic number, because the mean of its divisors is an integer number (6101114997).
Almost surely, 212202229993 is an apocalyptic number.
It is an amenable number.
12202229993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12202229993 is an equidigital number, since it uses as much as digits as its factorization.
12202229993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 12202229993 in words is "twelve billion, two hundred two million, two hundred twenty-nine thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •