Search a number
-
+
122024012002433 is a prime number
BaseRepresentation
bin11011101111101011101101…
…111000111011010010000001
3121000001101022012102222211222
4123233223231320323102001
5111443220134033034213
61111305020210244425
734462641525302222
oct3357535570732201
9530041265388758
10122024012002433
1135976102685902
12118290a2886715
135311a796004b8
14221bdca9a1249
15e191d06e5808
hex6efaede3b481

122024012002433 has 2 divisors, whose sum is σ = 122024012002434. Its totient is φ = 122024012002432.

The previous prime is 122024012002423. The next prime is 122024012002489. The reversal of 122024012002433 is 334200210420221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119309482260544 + 2714529741889 = 10922888^2 + 1647583^2 .

It is a cyclic number.

It is not a de Polignac number, because 122024012002433 - 218 = 122024011740289 is a prime.

It is a super-3 number, since 3×1220240120024333 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (122024012002423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61012006001216 + 61012006001217.

It is an arithmetic number, because the mean of its divisors is an integer number (61012006001217).

Almost surely, 2122024012002433 is an apocalyptic number.

It is an amenable number.

122024012002433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122024012002433 is an equidigital number, since it uses as much as digits as its factorization.

122024012002433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 26.

Adding to 122024012002433 its reverse (334200210420221), we get a palindrome (456224222422654).

The spelling of 122024012002433 in words is "one hundred twenty-two trillion, twenty-four billion, twelve million, two thousand, four hundred thirty-three".