Base | Representation |
---|---|
bin | 1011000110010001100010… |
… | …0100100010111000101001 |
3 | 1121012112120020100000100022 |
4 | 2301210120210202320221 |
5 | 3044411021031234233 |
6 | 41541413423250225 |
7 | 2366411126240555 |
oct | 261443044427051 |
9 | 47175506300308 |
10 | 12202414321193 |
11 | 398501884a278 |
12 | 1450aaba49975 |
13 | 6a68b4c70085 |
14 | 3028585aa865 |
15 | 16262d2e9398 |
hex | b1918922e29 |
12202414321193 has 2 divisors, whose sum is σ = 12202414321194. Its totient is φ = 12202414321192.
The previous prime is 12202414321151. The next prime is 12202414321267. The reversal of 12202414321193 is 39112341420221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7613256379369 + 4589157941824 = 2759213^2 + 2142232^2 .
It is a cyclic number.
It is not a de Polignac number, because 12202414321193 - 212 = 12202414317097 is a prime.
It is not a weakly prime, because it can be changed into another prime (12202414321693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6101207160596 + 6101207160597.
It is an arithmetic number, because the mean of its divisors is an integer number (6101207160597).
Almost surely, 212202414321193 is an apocalyptic number.
It is an amenable number.
12202414321193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12202414321193 is an equidigital number, since it uses as much as digits as its factorization.
12202414321193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 12202414321193 in words is "twelve trillion, two hundred two billion, four hundred fourteen million, three hundred twenty-one thousand, one hundred ninety-three".
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